2) \(a.\sqrt{\left(-15\right)^2}=\left|15\right|=15\)
\(b.\sqrt{\left(2-\sqrt{5}\right)^2}=\left|2-\sqrt{5}\right|=2-\sqrt{5}\)
\(c.\sqrt{\left(3-\sqrt{7}\right)^2}=\left|3-\sqrt{7}\right|=3-\sqrt{7}\)
\(d.2\sqrt{a^2}=\left|2\sqrt{a}\right|=2\sqrt{a}\)
bai1
a)
√x=5=> x=25
b)
√(x+1)=2; x+1=4;x=3
c)
√(x^2)=4=> x=±4; x>0=>x=4
d)
2√(x+1)=4=>√(x+1)=2
x+1=4;x=3
bai 2.
a)√(-15)^2=15
b)√[2-√5]^2=|2-√5|=√5-2
c)√(3-√7)^2=|3-√7|=3-√7
d)2√(a^2)=2|a|=-2a
e)
√(a-2); a<2; => ko ¥
câu b,c,d ghi nhầm
\(\sqrt{5}-2\)
\(\sqrt{7}-3\)
\(2\sqrt{a^2}=\sqrt{2^2.a^2}=\sqrt{\left(2.a\right)^2}=\left|2a\right|=2a\)