Question

Bài 1: Tìm x biết:

a) x - 6 : 2 - ( 48 - 24 . 2 : 6 - 3 ) = 0

b) \(\left(x-\frac{1}{3}\right)^2-\frac{1}{4}=0\)

Bài 2 : Tìm x,y \(\in\) N, biết:

\(2^x+624=5^y\)

giúp mk với !

Answer 1

Bài 1:

a) x-6:2-(48-24.2:6-3)=0

<=>x-3 - (48-8-3)=0

<=>x-3-37=0

<=>x-40=0

<=>x=0+40

=>x=40

b) \(\left(x-\frac{1}{3}\right)^2-\frac{1}{4}=0\\ < =>\left(x-\frac{1}{3}\right)^2=\frac{1}{4}\\ Mà:\left(\frac{1}{2}\right)^2=\frac{1}{4};\left(-\frac{1}{2}\right)^2=\frac{1}{4}\\ < =>\left(x-\frac{1}{3}\right)^2=\left(\frac{1}{2}\right)^2hoặc\left(x-\frac{1}{3}\right)^2=\left(-\frac{1}{2}\right)^2\\ < =>\left(x-\frac{1}{3}\right)=\frac{1}{2}hoặc\left(x-\frac{1}{3}\right)=-\frac{1}{2}\\ =>x=\frac{1}{2}+\frac{1}{3}hoặcx=-\frac{1}{2}+\frac{1}{3}\\ =>x=\frac{5}{6}hoặcx=-\frac{1}{6}\)

Answer 2

Bài 2: x=0; y=4