Question

Bài 1: Tìm x. a, 4x(x-5)+2x(8-2x)=-3. b, 2x-5(x-7)=4(3-2x)-2. ( Giúp mình vs thank nhiều ^^ 😘😘🤗🤗)

Answer 1

a, \(4x\left(x-5\right)+2x\left(8-2x\right)=-3\)

\(\Rightarrow4x^2-20x+16x-4x^2=-3\)

\(\Leftrightarrow-4x=-3\Leftrightarrow x=\dfrac{3}{4}\)

Vậy \(x=\dfrac{3}{4}\)

b, \(2x-5\left(x-7\right)=4\left(3-2x\right)-2\)

\(\Rightarrow2x-5x+35=12-8x-2\)

\(\Rightarrow2x-5x+8x=12-2-35\)

\(\Leftrightarrow5x=-25\Leftrightarrow x=-5\)

Vậy \(x=-5\)

Chúc bạn học tốt!!!

Answer 2

a) \(4x\left(x-5\right)+2x\left(8-2x\right)=-3\)

\(\Rightarrow4x^2-20+16x-4x^2=-3\)

\(\Rightarrow-20+16x=-3\)

\(\Rightarrow16x=-3+20=17\)

\(\Rightarrow x=\dfrac{17}{16}.\)

Vậy \(x=\dfrac{17}{16}.\)

b) Sửa đề đi.