a: \(P=\dfrac{\left(\sqrt{a}+2\right)^2}{\sqrt{a}+2}+\dfrac{\left(2-\sqrt{a}\right)\left(2+\sqrt{a}\right)}{2-\sqrt{a}}\)
\(=\sqrt{a}+2+\sqrt{a}+2=2\sqrt{a}+4\)
b: Để P=a+1 thì \(a+1-2\sqrt{a}-4=0\)
\(\Leftrightarrow\left(\sqrt{a}-3\right)\left(\sqrt{a}+1\right)=0\)
=>a=9