Gọi 3 số đó là a,b,c
Theo bài ra ta có:\(\left\{{}\begin{matrix}a+b+c=99\\\dfrac{a}{2}=\dfrac{b}{3}=\dfrac{c}{4}\end{matrix}\right.\)
\(\dfrac{a}{2}=\dfrac{b}{3}=\dfrac{c}{4}=\dfrac{a+b+c}{2+3+4}=\dfrac{99}{9}=11\)
\(\dfrac{a}{2}=11\Rightarrow a=22\\ \dfrac{b}{3}=11\Rightarrow b=33\\ \dfrac{c}{4}=11\Rightarrow c=44\)