a: \(=2\sqrt{x-3}+3\sqrt{x-3}-4\sqrt{x-3}+3-x\)
\(=\sqrt{x-3}+3-x\)
c: \(\Leftrightarrow7\sqrt{x-2}-2\sqrt{x-2}-3\sqrt{x-2}=18\)
=>2 căn x-2=18
=>x-2=81
=>x=83
Giải các phương trình sau:
a. \(\sqrt{25x+75}+3\sqrt{x-2}=2\sqrt{x-2}+\sqrt{9x-18}\)
b. \(\sqrt{\left(2x-1\right)^2}=4\)
c. \(\sqrt{\left(2x+1\right)^2}=3x-5\)
d. \(\sqrt{4x-12}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
Bài 1: Tìm x, biết
a)\(2\sqrt{9x-27}-\dfrac{1}{5}\sqrt{25x-75}-\dfrac{1}{7}\sqrt{49x-147}=20\)
b) \(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
c)\(\sqrt{16x-16}-\sqrt{9x-9}+\sqrt{4x-4}+\sqrt{x-1}=8\)
d) \(\sqrt{x+2\sqrt{x-1}}-\sqrt{x-2\sqrt{x-1}}=2\)
Giải các phương trình sau:
a. \(\sqrt{25x+75}+2\sqrt{9x+27}=5\sqrt{x+3}+18\)
b. \(\sqrt{4x-8}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
Tìm x biết:
a.\(\sqrt{18x}+2\sqrt{8x}-3\sqrt{2x}=12\)
b.\(\sqrt{9x+18}+2\sqrt{36x+72}-\sqrt{4x+8}=26\)
c.\(\sqrt{\left(x-2\right)^2}=10\)
d.\(\sqrt{9x^2-6x+1}=15\)
e.\(\sqrt{3x+4}=3x-8\)
giải phương trình
a)\(\sqrt{2x}-\sqrt{98}=0\)
b)\(\sqrt{2x}=\sqrt{8}\)
c)\(\sqrt{5x^2}=\sqrt{20}\)
d)\(\sqrt{2x}-3\sqrt{8x}+4\sqrt{32x}=52\)
e)\(3\sqrt{x-1}+2\sqrt{4x-4}-3\sqrt{9x-9}=-6\)
f)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
g)\(\sqrt{9x^2+18}+2\sqrt{x^2+2}-\sqrt{25x^2+50+3}=0\)
h)\(\sqrt{x-1}=\sqrt{3}\)
k)\(\sqrt{9x^2-6x+1}=3\)
l)\(\sqrt{2x-1}=2\)
m)\(\sqrt{x+2}=\sqrt{3-x}\)
n)\(\sqrt{4x^2}-4x+1=\sqrt{7-4\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
giải phương trình:
a) \(\sqrt{2x-3}=7\)
b)\(\sqrt{x^2-4x+4}=\sqrt{6-2\sqrt{5}}\)
c) \(\sqrt{3x+1}=\sqrt{4x-3}\)
d) \(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
Giải phương trình sau:
a) \(\sqrt{4x+20}-3\sqrt{5+x}+\dfrac{4}{3}\sqrt{9x+45}=6\)
b) \(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9x-9}+24\sqrt{\dfrac{x-1}{64}}=-17\)
c) \(2x-x^2+\sqrt{6x^2-12x+7}=0\)
d) \(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6\)
\(\sqrt{49x-98}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
Rút gọn các biểu thức sau:
a) \(A=3\sqrt{2x}-5\sqrt{8x}+7\sqrt{18x}+30\), \(x\ge0\)
b) \(B=4\sqrt{\dfrac{25x}{4}}-\dfrac{8}{3}\sqrt{\dfrac{9x}{4}}-\dfrac{4}{3x}\sqrt{\dfrac{9x^3}{64}}\), \(x>0\)
c) \(C=\dfrac{y}{2}+\dfrac{3}{4}\sqrt{1+9y^2-6y}-\dfrac{3}{2}\), \(y\le\dfrac{1}{3}\)
