Bài 6:
a: \(\Leftrightarrow\sqrt{3x-1}=17\)
=>3x-1=289
hay x=290/3
b: \(\Leftrightarrow\left|3x-1\right|=18\)
=>3x-1=18 hoặc 3x-1=-18
=>x=19/3 hoặc x=-17/3
c: \(\Leftrightarrow x+2=\dfrac{1}{4}\)
hay x=-7/4
d: \(\Leftrightarrow-2\sqrt{x}=-3\)
hay x=9/4
e: \(\Leftrightarrow\sqrt{2x+4}=6\)
=>2x+4=36
hay x=16
f: \(\Leftrightarrow\sqrt{x-3}=\dfrac{1}{2}\)
=>x-3=1/4
hay x=13/4
a)\(\sqrt{3x-1}-4=13\)
\(\Leftrightarrow\sqrt{3x-1}=17\)
`<=> 3x-1=289`
`<=> 3x = 290`
`<=> x = 290/3`
b)\(\sqrt{9x^2-6x+1}=18\)
\(\Leftrightarrow\sqrt{\left(3x-1\right)^2}=18\)
`<=> |3x-1|=18`
\(\Leftrightarrow\left[{}\begin{matrix}3x-1=18\\3x-1=-18\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=19\\3x=-17\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{3}\\x=-\dfrac{17}{3}\end{matrix}\right.\)
c)\(\sqrt{x}+2=\dfrac{1}{2}\)
\(\Leftrightarrow\sqrt{x}=-\dfrac{3}{2}\)
\(\Leftrightarrow x=\left(-\dfrac{3}{2}\right)^2=\dfrac{9}{4}\)
d)\(-2\sqrt{x}+3=0\)
\(\Leftrightarrow-2\sqrt{x}=-3\)
\(\Leftrightarrow\sqrt{x}=\dfrac{3}{2}\)
\(\Leftrightarrow x=\dfrac{9}{4}\)
e)\(\dfrac{\sqrt{2x+4}}{2}=3\)
`<=>\sqrt{2x+4} = 6`
`<=>2x+4 = 36`
`<=> 2x = 32`
`<=> x= 16`
f)\(\dfrac{2}{\sqrt{x-3}}=4\)
`<=> 4\sqrt{x-3}= 2`
`<=>\sqrt{x-3}= 1/2`
`<=> x-3 = 1/4`
`<=> x =13/4`
\(\sqrt{3x-1}-4=13\\ \text{Đ}K:x\ge\dfrac{1}{3}\\ \Leftrightarrow3x-1=289\\ \Leftrightarrow3x=290\Leftrightarrow x=\dfrac{290}{3}\\ \)
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