\(3\cdot\left(x+\dfrac{1}{2}\right)=\dfrac{7}{4}-\dfrac{2}{3}\)
\(3\cdot\left(x+\dfrac{1}{2}\right)=\dfrac{21}{12}-\dfrac{8}{12}\)
\(3\cdot\left(x+\dfrac{1}{2}\right)=\dfrac{13}{12}\)
\(x+\dfrac{1}{2}=\dfrac{13}{12}\cdot\dfrac{1}{3}\)
\(x+\dfrac{1}{2}=\dfrac{13}{36}\)
\(x=\dfrac{13}{36}-\dfrac{1}{2}=\dfrac{13}{36}-\dfrac{18}{36}\)
\(x=-\dfrac{5}{36}\)
\(\left(2x-5\right)^2=81\)
\(4x^2-20x+25=81\)
\(4x^2-20x-56=0\)
\(4\cdot\left(x+2\right)\left(x-7\right)=0\)
\(\left[{}\begin{matrix}x+2=0\\x-7=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-2\\x=7\end{matrix}\right.\Rightarrow x\in\left\{-2;7\right\}\)
\(\left(3x-4\right)^3=27\)
\(\left(3x-4\right)^3=3^3\)
`=>3x-4=3`
`3x=7`
`=>x=7/3`
