a) \(12x-60+21-7x-5=0\)
\(\Rightarrow5x-44=0\)
\(\Rightarrow5x=44\)
\(\Rightarrow x=\frac{44}{5}\)
Vậy: \(x=\frac{44}{5}\)
b) \(2x^2-3=29\)
\(\Rightarrow2x^2=3+29=32\)
\(\Rightarrow x^2=\frac{32}{2}=16\)
\(\Rightarrow x=\sqrt{16}=4\)
Vậy: \(x=4\)