Question

a, x+3 /8= 2/x-3 help help me

Answer 1

\(\frac{x+3}{8}=\frac{2}{x-3}\)

\(\left(x+3\right)\times\left(x-3\right)=2\times8\)

\(x^2-3^2=16\)

\(x^2-9=16\)

\(x^2=16+9\)

\(x^2=25\)

\(x^2=\left(\pm5\right)^2\)

\(x=\pm5\)

Vậy x = 5 hoặc x = -5

 

 

Answer 2

\(\frac{x+3}{8}=\frac{2}{x-3}\)

\(\Rightarrow\left(x+3\right)\left(x-3\right)=2.8=16\)

\(\Rightarrow x^2-3^2=16\)

\(\Rightarrow x^2=16+3^2=25\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)