Perimeters of a triangle is: 6.2+8.3+9.5=24cm
But a square and a triangle have equal perimeters
⇒Perimeters of a square is 24cm
So: the side of a square=\(\dfrac{24}{4}\)=6
Other way: the area of a square=a.a
⇔Ssquare=6*6=36 (cm2)
Perimeters of a triangle is: 6.2+8.3+9.5=24cm
But a square and a triangle have equal perimeters
⇒Perimeters of a square is 24cm
So: the side of a square=\(\dfrac{24}{4}\)=6
Other way: the area of a square=a.a
⇔Ssquare=6*6=36 (cm2)
Given that ABCD is a rectangle with AB = 12 cm, AD = 6 cm. M and N are respectively midpoint of segments BC and CD. Find the area of triangle AMN in square centimeters.
Let a, b and c be positive integers. The sum of 160 and the square of a is equal the sum of 5 and the square of b. The sum of 320 and the square of a is equal to the sum of 5 and the square of c, a is
A trapezuim ABCD has two parallel sides AB and CD. The diagonals AC and BD intersect at E. If the areas of triangle CDE and CDB are 1 and 4 respectively, what is the area of the trapezuim ABCD
A box contains 50 blue square cards whose the side length are 2 cm, 4 cm, 6 cm, ..., 100 cm, respectively and 50 red square cards with side lengths are 1 cm, 3 cm, 5 cm, ..., 99 cm, respectively. The total area of the blue cards is greater than the total area of the red care is .... cm2
Let ABCD be a trapezoid with bases AB, CD and O be the intersection of AC and BD. If the areas of triangle OAB, triangle OCD are 16cm2, 40cm2respectively and M is the midpoint of BD, then the area of the triangle AMD is .........cm2.
Let ABC be an isoceles triangle (AB = AC) and its area is 501cm2. BD is the internal bisector of the angle ABC (D ∈ AC), E is a point on the opposite ray of CA such that CE = CB. I is a point on BC such that CI = 1/2 BI. The line EI meets AB at K, BD meets KC at H. Find the area of the triangle AHC.
A rectangle has a length of 60cm and a width of 30cm. It is cut into 2 indentical squares, 2 identical rectangles and a shaded small square. Find the area of the shaded square.
Find the area of the shaded square.
Question 1:In a magic triangle, each of the six whole numbers 10; 11; 12; 13; 14; 15 is placed in one of the circles so that the sum, S, of the three numbers on each side of the triangle is the same. The largest possible value for S is____
Q2:Find the highest common factor of 147x and 98y if HCF(x;y)=1
Q3: A pattern of triangles is made from matches shown as follows
if there are 207 matches used, how many triangles has been formed