a) Số mol rượu:
\(250.45\%=112,5\left(ml\right)\)
b)Số mol rượu:
\(500.45\%=225\left(ml\right)\)
Thể tích rượu 25 độ:
\(\frac{225.100}{25}=900\left(ml\right)=0,9\left(l\right)\)
a) VC2H5OH= 45*250/100=112.5g
mC2H5OH= 112.5*0.8=90g
nC2H5OH= 90/46 \(\simeq\)2 mol
b) VC2H5OH ( 45o) = 500*45/100=225ml
Vhh C2H5OH ( 25o) = 225*100/25=900ml