ĐKXĐ: \(x>0\)
\(VT=8x^2+\frac{1}{4\sqrt{x}}+\frac{1}{4\sqrt{x}}+\frac{1}{4\sqrt{x}}+\frac{1}{4\sqrt{x}}\)
\(VT\ge5\sqrt[5]{\frac{8x^2}{4^4x^2}}=\frac{5}{2}\)
Dấu "=" xảy ra khi và chỉ khi:
\(8x^2=\frac{1}{4\sqrt{x}}\Leftrightarrow\sqrt{x^5}=\frac{1}{32}\Rightarrow x=\frac{1}{4}\)
Cho A = \(\frac{2x+15\sqrt{x}+18}{x+3\sqrt{x}-18}+\frac{3x+4\sqrt{x}+1}{2x-3\sqrt{x}-5}-\frac{8x-15\sqrt{x}}{2x\sqrt{x}-11x+5\sqrt{x}}\)
Tính A tại \(x=\sqrt[3]{2+\sqrt{5}}+\sqrt[3]{2-\sqrt{5}}\)
Bài 1: Tính :
\(C=\sqrt{\frac{3\sqrt{3}-4}{2\sqrt{3}+1}}-\sqrt{\frac{\sqrt{3}+4}{5-2\sqrt{3}}}\)
\(B=\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+....+\frac{1}{\sqrt{99}+\sqrt{100}}\)
\(D=\sqrt{1+\sqrt{3+\sqrt{13+4\sqrt{3}}}}+\sqrt{1-\sqrt{3-\sqrt{13-4\sqrt{3}}}}\)
Bài 2 : Cho \(P=\left(\frac{1}{\sqrt{x}-1}+\frac{x-\sqrt{x}+6}{x+\sqrt{x}-2}\right):\left(\frac{\sqrt{x}+1}{\sqrt{x}+2}+\frac{x-\sqrt{x}-2}{x+\sqrt{x}+2}\right)\)
a, Rút gọn P
b, Tìm GTNN
c, Tìm x để \(P.\frac{x-1}{x^2+8x}< -2\)
P=\(\left(\frac{4\sqrt{x}}{2-\sqrt{x}}-\frac{8x}{4-x}\right):\left(\frac{\sqrt{x}-4}{x+2\sqrt{x}}+\frac{1}{\sqrt{x}}\right)\)
Rút gọn
gpt : a) \(\frac{5x}{\sqrt{4-x^2}}+\frac{8}{x^2}+\frac{2x}{4-x^2}+\frac{5\sqrt{4-x^2}}{x}+4=0\)
b) \(\frac{2x}{\sqrt{8x^2+25}}+\frac{125}{x^2}-14=0\)
c) \(\left(x^3-3x+2\right)\sqrt{3x-2}-2x^3+6x^2-4x=0\)
d) \(\sqrt{x^2-x+6}+\frac{4}{x-1}=x^2+x\)
1) Giaỉ hệ \(\left\{{}\begin{matrix}\left(x+y\right)^2\left(8x^2+8y^2+4xy-13\right)+5=0\\2x+\frac{1}{x+y}=1\end{matrix}\right.\)
2) Tính P\(=\frac{4\left(x+1\right)x^{2018}-2x^{2017}+2x+1}{2x^2+3x}\)Với x\(=\sqrt{\frac{1}{2\sqrt{3}-2}-\frac{3}{2\sqrt{3}+2}}\)
Giải phương trình sau:
\(\sqrt{\frac{1-2x}{x}}=\frac{3x+x^2}{x^2+1}\)
\(x^2-3x+1=-\frac{\sqrt{3}}{3}\sqrt{x^4+x^2+1}\)
\(x^2-\sqrt{x^3+x}=6x-1\)
\(3\sqrt{x^2-\frac{1}{4}+\sqrt{x^2+x+\frac{1}{4}}}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\)
\(x^2+\frac{8x^3}{\sqrt{9-x^2}}=9\)
cho biểu thức P=\(\left(\frac{4\sqrt{x}}{2-\sqrt{x}}-\frac{8x}{4-x}\right):\left(\frac{\sqrt{x}-4}{x+2\sqrt{x}}+\frac{1}{\sqrt{x}}\right)\)
tìm điều kiện của x để P có nghĩa, rút gọn P
\(\frac{x^3}{\sqrt{5-x^2}}+8x^2=40\)
Cho \(8x^3=11y^3=26z^3\) và \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1\)
Tính \(A=\sqrt{8x^2+11y^2+26z^2}\)
