Question

4(x-3) =7^2-1^10

Answer 1

\(4\left(x-3\right)=7^2-1^{10}\\ < =>4\left(x-3\right)=49-1=48\\ =>x-3=\dfrac{48}{4}=12\\ =>x=12+3=15\)

Answer 2

\(4\left(x-3\right)=7^2-1^{10}\)

= \(4\left(x-3\right)=49-1\)

= \(4\left(x-3\right)=48\)

= \(x-3=48:4=12\)

=\(x=12+3=15\)

\(\Rightarrow x=15\)

Answer 3

\(4\left(x-3\right)=7^2-1^{10}\)

\(\Rightarrow4x-12=49-1\)

\(\Rightarrow4x=49-1+12\Rightarrow4x=60\Rightarrow x=15\)

Vậy \(x=15\)

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