\(\left(4x-1\right)\left(4x-1\right)^2-\left(4x-3\right)\left(16x^2+3\right)\)
\(=\left(4x-1\right)^3-\left(4x-3\right)\left(16x^2+3\right)\)
\(=64x^3-48x^2+12x-1-64x^3-12x+48x^2-9\)
=-10
(4x−1)(4x−1)^2−(4x−3)(16x2+3))
=(4x−1)^3−(4x−3)(16x2+3)
=64x^3−48x^2+12x−1−64x^3−12x+48x^2−9
=-1-9
=-10
Giải:
\(\left(4x-1\right)\left(4x-1\right)^2-\left(4x-3\right)\left(16x^2+3\right)\)
= \(\left(4x-1\right)^3-\left(4x-3\right)\left(16x^2+3\right)\)
= \(64x^3-48x^2+12x-1-64x^3-12x+48x^2-9\)
= \(-10\)
Hok tốt 
