Bài 2: Căn thức bậc hai và hằng đẳng thức căn bậc hai của bình phương
Các câu hỏi tương tự
50. √(98-16√3)
51. √(2-√3)
52. √(4+√15)
53. √(5-√21)
54. √(6-√35)
55. √(2+√3)
56. √(4-√15)
57. √(8-√55)
58. √(7+√33)
59. √(6+√35)
60. √(7-3√5)
1)\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
2)\(\sqrt{35+12\sqrt{6}}-\sqrt{35-12\sqrt{6}}\)
3)\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
12) √15-6√6 + √35-12√6
13) √46-6√5 - √29-12√5
14) (2-√3) √7+4√3
15) (4+√5)(√10-√6) √4-√15
16) √25-16 -6√1/3 - 2/1+√3
17) (1+√2+√3) (1+√2-√3)
\((4-\sqrt{15}).(\sqrt{2-\sqrt{3}}+\sqrt{3+\sqrt{5}})^2\)
14. √(7-4√3)
15. √(8+2√15)
16. √(10-2√21)
17. √(11+2√18)
18. √(7+2√10)
19. √(7+4√3)
20. √(12-2√35)
Tính
A sqrt{4+sqrt{15}}- sqrt{4-sqrt{15}} -sqrt{2-sqrt{3}}
B sqrt{9-2sqrt{14}} +sqrt{9-2sqrt{14}}
C left(4+sqrt{15}right) left(sqrt{10}-sqrt{6}right) sqrt{4-sqrt{15}}
D dfrac{2+sqrt{3}}{sqrt{2}+sqrt{2}+sqrt{3}} + dfrac{2-sqrt{3}}{sqrt{2}-sqrt{2sqrt{3}}}
Đọc tiếp
Tính
A= \(\sqrt{4+\sqrt{15}}\)- \(\sqrt{4-\sqrt{15}}\) -\(\sqrt{2-\sqrt{3}}\)
B= \(\sqrt{9-2\sqrt{14}}\) +\(\sqrt{9-2\sqrt{14}}\)
C= \(\left(4+\sqrt{15}\right)\) \(\left(\sqrt{10}-\sqrt{6}\right)\) \(\sqrt{4-\sqrt{15}}\)
D= \(\dfrac{2+\sqrt{3}}{\sqrt{2}+\sqrt{2}+\sqrt{3}}\) + \(\dfrac{2-\sqrt{3}}{\sqrt{2}-\sqrt{2\sqrt{3}}}\)
Rút gọn\(B=\frac{3\sqrt{8}+2\sqrt{12}+\sqrt{20}}{3\sqrt{18}-2\sqrt{27}+\sqrt{45}}\\ C=\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
1.Tính :
a.\(-\frac{4}{3}.\sqrt[]{\left(-0.4\right)^2}\)
b.\(5.\sqrt{\left(-\frac{1}{5}\right)^2}\)
c.\(4.\sqrt[]{\left(-3\right)^6+5.\sqrt[]{\left(-2\right)^4}}\)
d.\(3.\sqrt[]{\left(-15\right)^2}-4.\sqrt[]{\left(-0.5\right)^2}\)
rút gon
\(\sqrt{8+2\sqrt{15}}\)-\(\sqrt{8-2\sqrt{15}}\)
\(\sqrt{4+2\sqrt{3}}\)+\(\sqrt{4-2\sqrt{3}}\)