\(3^{x+1}+3^{x+2}-2.3^x=30\)
\(3^x.\left(3^1+3^2-2\right)=30\)
\(3^x.10=30\)
\(3^x=3\)
\(=>x=1\)
Đề bài là thế này à/
\(3x+3^{x+2}-2x.3^x\\\)
\(3^{x+1}+3^{x+2}-2.3^x=30\)
\(\Rightarrow3^x.3^1+3^x.3^2-2.3^x=30\)
\(\Rightarrow3^x.3+3^x.9-3^x.2=30\)
\(\Rightarrow3^x\left(3+9-2\right)=30\)
\(\Rightarrow3^x.10=30\)
\(\Rightarrow3^x=3\)
\(\Rightarrow x=1\)