Question

(3x+2)(2y-3)=6xy (4x+5)(y-5)=4xy

Answer 1

\(\left\{{}\begin{matrix}\left(3x+2\right)\left(2y-3\right)=6xy\\\left(4x+5\right)\left(y-5\right)=4xy\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}6xy-9x+4y-6=6xy\\4xy-20x+5y-25=4xy\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}-9x+4y=6\\-20x+5y=25\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}-\dfrac{45}{4}x+5y=\dfrac{15}{2}\\-20x+5y=25\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}-\dfrac{45}{5}x+5y=\dfrac{15}{2}\\\dfrac{35}{4}x=\dfrac{35}{2}\end{matrix}\right.\)

⇔\(\left\{{}\begin{matrix}x=2\\y=3\end{matrix}\right.\)

Vậy HPT có nghiệm (x;y) = (2;3)