Question

(3x+2)^2-(3x-2)^2=5x+38

Làm nhanh hộ mình cảm ơn

Mai mình nộp rồi

^2 là mũ 2 nha

Answer 1

\(\left(3x+2\right)^2-\left(3x-2\right)^2=5x+38\)

\(\Leftrightarrow\left(9x^2+12x+4\right)-\left(9x^2-12x+4\right)=5x+38\)

\(\Leftrightarrow24x=5x+38\Leftrightarrow19x=38\Leftrightarrow x=\frac{38}{19}=2\)

Vậy $x=2$

Answer 2

(3x+2)²-(3x-2)²=5x+38

⇒(3x+2-3x+2)(3x+2+3x-2)=5x+38

⇒4.6x=5x+38

⇒19x=38

⇒x=2

Vậy...