\(\left(3x+1\right)^3=64\)
\(\Rightarrow\left(3x+1\right)^3=4^3\)
\(\Rightarrow3x+1=4\)
\(\Rightarrow3x=3\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
\(\left(3x+1\right)^3=64\Rightarrow\left(3x+1\right)^3=4^3\)
\(\Rightarrow3x+1=4\Rightarrow3x=5\Rightarrow x=\frac{5}{3}\)
( 3x+1)^3=64
=> ( 3x+1)^3= 4^3
=> 3x+1=4
=> 3x=3
=>x=1
Học tốt ! Nguyễn Thị Ngọc Linh