Ta có:64=8\(^2\)
\(\Rightarrow\)3x-1=8
3x=8+1
3x=9
x=9:3
x=3
Vậy x=3.
\(\left(3x-1\right)^2=64\)
\(\Rightarrow\left(3x-1\right)^2=8^2\)
\(\Rightarrow3x-1=8\)
\(\Rightarrow3x=9\)
\(\Rightarrow x=3\)
Vậy x = 3
Ta có:
\(\left(3x-1\right)^2=64\)
\(\Rightarrow\)\(\left(3x-1\right)^2=8^2\)
\(\Rightarrow\)\(3x-1=8\)
\(3x=8+1\)
\(3x=9\)
\(x=9:3\)
\(x=3\)
Vậy x = 3
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