\(\left(3x+1\right)^2+\left(3x-1\right)^2-2\left(3x-1\right)\left(3x+1\right)\)
\(=\left(3x+1\right)^2-2.\left(3x+1\right)\left(3x1\right)+\left(3x-1\right)^2\)
\(=\left(3x+1-3x+1\right)^2\)
\(=2^2=4\)
(3x2-6x):3x(3x-1)2:(3x-1)
Bài 1 : Thực hiện phép tính :
a. ( 3x+5)^2
b.(2x-3y)^2
c.(4x^2-5y)^2
d.(2xy+3y)^2
e.(3x+5)^2-9(x-2)^2
f.(x+y)^2+(x-y)^2
g.(2a-b)^2-(2a+b)^2
Bài 2 : Tìm x :
a.(3x-4)(3x+4)-(3x+1)^2=0
b.(2x-5)^2-(2x+1)(2x-1)=10
c.(3x-1)^2+2(3x-1)(3-x)+(3-x)^2=25
(1-3x)2 - (x-2)(9x+1) = (3x-4)(3x+4) - 9(x+3)2
(2x+2).(2x+2)-(3x-1).(3x+1)
Tìm x,biết:
a) 3(2x-1) -5(x-3) +6(3x-4) = 24
b) 2x2 + 3(x2 -1) = 5x (x+1)
c) 2x(5-3x) + 2x(3x-5) -3(x-7) = 3
d) 3x(x+1) -2x(x+2) = -1-x
e) 3x(x-2) -x(1+3x) = 14
f) 2x(x+3) -3(x2 + 1) = x+1 -x(x-2)
giúp mik nha !!!! :D
1/ rút gọn biểu thức sau: (3x-1)^2+2(3x-1)(2x+1)+(2x+1)^2
2/ phân tích đa thức sau thành nhân tử:
a) x^2-9+(x-3)
b) x^3-3x^2+3x-1
Tìm x, biết
a) ( x^2 -1/2.x ) :2x + ( 3x - 1 )^2 : ( 1-3x) =0
b) ( x-1)^3 + 1 + 3x( x - 4) = 0
(3x-1) (9x^2+3x+1)
tìm x, biết
5x (3x-1) + x(3x-1) - 2 (3x-1) =0
