Question

(3x-1) (2x-3) (x+5) = 0

Answer 1

\(\left(3x-1\right)\left(2x-3\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}3x-1=0\\2x-3=0\\x+5=0\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}3x=1\\2x=3\\x=-5\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=\frac{1}{3}\\x=\frac{3}{2}\\x=-5\end{matrix}\right.\)

Answer 2

(3x-1)(2x-3)(x+5)=0

<=>\(\left[{}\begin{matrix}3x-1=0< =>3x=1< =>x=\frac{1}{3}\left(tm\right)\\2x-3=0< =>2x=3< =>x=\frac{3}{2}\left(tm\right)\\x+5=0< =>x=-5\left(tm\right)\end{matrix}\right.\)

vậy pt có tập nghiệm S={​\(\frac{1}{3},\frac{3}{2},-5\)

Answer 3

(3x-1)(2x-3)(x-5)=0

3x-1 = 0 3x = 1 x = \(\frac{1}{3}\)

⇌ 2x-3 = 0 ⇌ 2x = 3 ⇌ x = \(\frac{2}{3}\)

x-5 = 0 x = 5 x = 5

Vậy x = {\(\frac{1}{3};\frac{2}{3}\);5}