\(\dfrac{3}{5}\cdot\dfrac{13}{46}-\dfrac{1}{10}\cdot\dfrac{16}{23}=\dfrac{39}{230}-\dfrac{8}{115}=\dfrac{1}{10}\).
\(\dfrac{3}{5}\cdot\dfrac{13}{46}-\dfrac{1}{10}\cdot\dfrac{16}{23}=3\cdot\dfrac{1}{5}\cdot\dfrac{1}{2}\cdot\dfrac{13}{23}-\dfrac{1}{10}\cdot\dfrac{16}{23}=3\cdot\dfrac{1}{10}\cdot\dfrac{13}{23}-\dfrac{1}{10}\cdot\dfrac{16}{23}=\dfrac{1}{10}\left(3\cdot\dfrac{13}{23}-\dfrac{16}{23}\right)=\dfrac{1}{10}\left(\dfrac{39}{23}-\dfrac{26}{23}\right)=\dfrac{1}{10}\cdot\dfrac{23}{23}=\dfrac{1}{10}\cdot1=\dfrac{1}{10}\).