\(-2x+3\left(x-2\right)+9=12+4x\)
\(\Rightarrow-2x+3x-6+9-4x=12\)
\(\Rightarrow-3x=12+6-9\)
\(\Rightarrow-3x=9\Rightarrow x=-3\)
Vậy..............
\(-2.x+3.(x-2)+9=12+4x\)
\(\Leftrightarrow-2.x+3.x+3.\left(-2\right)+9=12+4x\)
\(\Leftrightarrow-2x+3x-6+9=12+4x\)
\(\Leftrightarrow-2x+3x-4x=12+6-9\)
\(\Leftrightarrow-3x=9\)
\(\Leftrightarrow x=\dfrac{9}{-3}\)
\(\Leftrightarrow x=-3\)
Vậy \(x=-3\)