áp dụng dãy tỉ số bằng nhau ta có
\(\dfrac{2x}{3}=\dfrac{3y}{4}=\dfrac{4z}{5}=\dfrac{2x+3y+4z}{3+4+5}=\dfrac{49}{12}\)
\(\dfrac{2x}{3}=\dfrac{49}{12}=>x=\dfrac{49}{12}\cdot3:2=\dfrac{49}{8}\)
\(\dfrac{3y}{4}=\dfrac{49}{12}=>y=\dfrac{49}{12}\cdot4:3=\dfrac{49}{9}\)
\(\dfrac{4z}{5}=\dfrac{49}{12}=>z=\dfrac{49}{12}\cdot5:4=\dfrac{245}{48}\)