\(\Leftrightarrow\left(2x^2-3x+2\right)^2=\left(-x+1\right)^2\)
\(\Leftrightarrow\left(2x^2-3x+2\right)^2-\left(-x+1\right)^2=0\)
\(\Leftrightarrow\left(2x^2-4x+3\right)\left(2x^2-2x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x^2-4x+3=0\\2x^2-2x-1=0\end{matrix}\right.\) (bấm máy)
Tìm m để pt -2x2-3x -m+1 =0 có 2 nghiệm âm phân biệt.
1) \(\sqrt{x^2-4x+5}+3=4x-x^2\)
2) \(4\sqrt{x^2-6+6}=x^2-6x +9\)
3) \(\sqrt{x^2-3x^3}+\sqrt{x^2-3x+6}=3\)
4) \(\sqrt[3]{2-x}=1-\sqrt{x-1}\)
Gpt.
1,3√(3x+1)+10√(2-x)=13x-20√(-3x^2+5x+2)+9
2,(4x-1)√(x^2+16)=2x^2+2x+31
1. | x^3 -8| > 2-x
2. | x^2 -3x +2| >= | x^2 +3x +2|
3. | (x^2 -4x)/x^2 + x+2| <=1
4. | ( x^2-5x+4)/ x^2-4 | <= 1
5. | 1-2/x^2| >= x^2
6. | (2-3|x| )/ 1+x) <= 1.
\(\frac{x\left(3x-1\right)}{2-\sqrt{4+x-3x^2}}\le\frac{1}{2}\)
giải các phương trình và hệ phương trình sau
1 , 4 ( x + 5 ) ( x + 6 ) ( x + 10 ) ( x + 12 ) = 3x2
2 , ( 2x - 1 ) ( 4x + 5 ) ( 8x + 3 ) ( 16x - 15 ) = 99x2
3 ,( x - 1 ) ( x - 2 ) ( x - 4 ) ( x - 8 ) =\(\frac{10}{9}\) x2
4, \(\frac{3x}{x^2-x+4}\) + \(\frac{x}{2x^2-6x+8}\) = 1
5 , \(\frac{3x}{x^2-4x+1}\) - \(\frac{2x}{x^2+x+1}\) = \(\frac{8}{3}\)
6, \(\frac{3x}{x^2-3x+1}\) + \(\frac{7x}{x^2+x+1}\) = -4
7, \(\frac{4x}{4x^2-8x+7}\) + \(\frac{3x}{4x^2-10x+7}\)= 1
8, \(\frac{2x}{x^2-3x+1}\) + \(\frac{7x}{x^2+x+1}\) = 6
9, \(\frac{x^2-10x+15}{x^2-6x+15}\) - \(\frac{4x}{x^2-12x+15}\)= 2
giải hệ bất phương trình sau :
\(\left\{{}\begin{matrix}\frac{3x^2-7x+8}{x^2+1}>1\\\frac{3x^2-7x+8}{x^2+1}< 2\end{matrix}\right.\)
\(x^3+3x^2-3\sqrt[3]{3x+5}+1-3x\)
mn giải hộ tôi mới..
x^4+3x^3-2x^2+3X+1=0
x^4-2x^3-5x^2+2x+1=0
Giải phương trình :
\(2\left(2x^2-3x+1\right)^2-3\left(2x^2-3x+1\right)+1=x\)
