\(2^{x+1}-2^x=32\)
\(\Leftrightarrow2^x.\left(2-1\right)=32\)
\(\Leftrightarrow2^x.1=32=2^5\)
\(\Leftrightarrow x=5\)
Vậy x = 5
2^x+1-2^x=32
\(\Rightarrow\)(2^x).2-(2^x).1=32
(2^x).(2-1)=32
\(\Rightarrow\)2^x=32
2^x=2^5
\(\Rightarrow\)x=5\(\in\)N.
Vậy x=5.