\(\left|x+1\right|=\frac{3}{4}-\frac{2}{5}\)
\(\left|x+1\right|=\frac{7}{20}\)
TH1: \(x+1=\frac{-7}{20}\)
\(x\) \(=\frac{-7}{20}-1\)
\(x\) \(=\frac{-27}{20}\)
TH2 : \(x+1=\frac{7}{20}\)
\(x\) \(=\frac{7}{20}-1\)
\(x\) \(=\frac{-7}{20}\)
Vậy x ∈ \(\left\{\frac{-27}{20};\frac{-7}{20}\right\}\)
\(\frac{2}{5}\)+|\(x\)+1|=\(\frac{3}{4}\)
=>|\(x\)+1|=\(\frac{3}{4}\)-\(\frac{2}{5}\)
=>|x+1|=\(\frac{7}{20}\)
=>\(\left[{}\begin{matrix}x+1=\frac{7}{20}\\x+1=\frac{-7}{20}\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=\frac{7}{20}-1\\x=\frac{-7}{20}-1\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=\frac{-13}{20}\\x=\frac{-27}{20}\end{matrix}\right.\)
