Question

(2,5-3\(x\)) : 1\(\frac{2}{3}\)=(\(\frac{8}{5}\)+2\(x\)): (\(-\frac{8}{17}\))

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Answer 1

\(\left(2,5x-3x\right);1\frac{2}{3}=\left(\frac{8}{5}-2x\right):\left(-\frac{8}{17}\right)\)

⇔\(\left(2,5-3x\right).\frac{3}{5}=\left(\frac{8}{5}+2x\right).\left(-\frac{17}{8}\right)\)

⇔\(\frac{3}{2}-\frac{9x}{5}=-\frac{17}{5}-\frac{17x}{4}\)

⇔\(\frac{3}{2}-\frac{9x}{5}+\frac{17}{5}+\frac{17}{5}=0\)

⇔\(\frac{30}{20}-\frac{36x}{20}+\frac{68}{20}+\frac{85x}{20}=0\)

⇔\(\frac{30-36x+68+85x}{20}=0\)

⇔\(\frac{98+49x}{20}=0\)

⇔\(\frac{49\left(2+x\right)}{20}=0\)

⇔\(2+x=0\)

⇔\(x=-2\)