\(\left(2+2x\right)\cdot3\dfrac{5}{6}=46\)
\(\left(2+2x\right)\cdot\dfrac{23}{6}=46\)
\(2+2x=46:\dfrac{23}{6}\)
\(2+2x=46\cdot\dfrac{6}{23}\)
\(2+2x=12\)
\(2x=12-2\)
\(2x=10\)
\(x=10:2\)
\(x=5\)
Vậy \(x=5\).
(2+2x) . 3 5/6 = 46
=> (2+2x) . 23 = 46
=> 2 + 2x = 46 : 23
=> 2 + 2x = 2
=> 2x = 0
=>x = 0
( 2 + 2x ) . \(3\dfrac{5}{6}\)= 46
( 2 + 2x ) . \(\dfrac{23}{6}\)=46
2 + 2x = 46 : \(\dfrac{23}{6}\)
2+ 2x = 12
2x = 10
x = 5