Question

\(2018x+4036=x^2+4x+4\)

Answer 1

Giải:

\(2018x+4036=x^2+4x+4\)

\(\Leftrightarrow2018\left(x+2\right)=\left(x+2\right)^2\)

\(\Leftrightarrow2018\left(x+2\right)-\left(x+2\right)^2=0\)

\(\Leftrightarrow\left(x+2\right)\left(2018-x-2\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(2016-x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=0\\2016-x=0\end{matrix}\right.\left[{}\begin{matrix}x=-2\\x=2016\end{matrix}\right.\)

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