nhìn đề bài mà trả hiểu là trừ hay trị tuyệt đối nữa
https://olm.vn/hoi-dap/question/630254.html
Tìm x:
\(\dfrac{x}{-18}=\dfrac{-50}{x};\\ 1\dfrac{1}{3}:\left(-0,08\right)=\dfrac{2}{3}:\left(-0,1x\right);\\ x=\dfrac{a}{b+c}=\dfrac{b}{c+a}=\dfrac{c}{b+a};\\ \dfrac{x^2}{6}=\dfrac{24}{25};\dfrac{x+1}{x-5}=\dfrac{0,5}{0,6};\\ \dfrac{2}{3}x:\dfrac{1}{5}=1\dfrac{1}{3}:\dfrac{1}{4};\\ 1,35:0,2=1,25:0,1x\)
1. tìm x |x| + x = 0 x + |x| = 2x x/|x| = -1 |3x-2| = x |x-2| = 2x + 1
2.tìm x , y, z thuộc Q |x +19/5| + | y + 1890/1975| + | z- 2004 | = 0 |x- 1/2| + | y+ 3/2 | + | x -y -z -1/2 | = 0
|15/32 - x | + |4/25 - y| + | z- 13/31| < 0
Tìm \(x\in Z\),biết:
a/\(x^2=16\)
b/\(x^3=-8\)
c/\(\left(x+2\right)^2=4\)
d/\(\left(1-x\right)^3=1\)
e/\(\dfrac{1}{4}.\dfrac{1}{6}.\dfrac{3}{8}.\dfrac{4}{10}.....\dfrac{14}{30}.\dfrac{15}{32}=2^x\)
Bài 1: tìm GTLN:
a) D=1-|2x-3|
b) E=-|10-5x|-14,2
c) P=4-|5x-2|-|3y+12|
d) A= 5-3(2x-1)2
BÀI 2: TÍNH:
A=|x+\(\dfrac{1}{2}\)|-|x+2|+|x-\(\dfrac{3}{4}\)| khi x=\(\dfrac{-1}{2}\)
B= 2x+2xy-y với |x|=2,5;y=\(\dfrac{-3}{4}\)
C=3a-3ab-b; B=\(\dfrac{5a}{3}-\dfrac{3}{b}\)
Mong mn giúp mk vs, mk đang cần gấp
Help me ..........................!
1.Tìm x ,biết : \(|\left|x-1\right|+2|=3\)
tìm x
a) x+10=25
b)\(\frac{2}{3}\)x-\(\frac{1}{2}\)=\(\frac{1}{10}\)
c)\(\frac{x}{7}\)=\(\frac{-6}{21}\)
d)|\(\frac{2}{3}\)x-\(\frac{1}{2}\)|=\(\frac{5}{6}\)
1)Tìm x;y;z biết
a) \(\dfrac{x-1}{2}=\dfrac{y-2}{3}=\dfrac{z-3}{4}\) và \(2x+3y-z=50\)
2)Cho \(x\ne0;y\ne0;z\ne0\) và \(x-y-z=0\)
Tính:\(B=\left(1-\dfrac{z}{x}\right).\left(1-\dfrac{x}{y}\right).\left(1+\dfrac{y}{z}\right)\)
(-2x3y2)+\(\dfrac{1}{2}\)x3y5(\(\dfrac{-2}{3}\)x6y7)
Tìm x:
a/\(\left(5x+1\right)^2=\dfrac{36}{49}\)
b/\(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
c/\(\left(8x+1\right)^{2n+1}=5^{2n+1}\left(n\in N\right)\)
