Bài 1:
\(pt\Leftrightarrow\dfrac{xy}{8y}-\dfrac{16}{8y}=\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{xy-16}{8y}=\dfrac{3}{4}\Leftrightarrow4\left(xy-16\right)=3\cdot8y\)
\(\Leftrightarrow xy-16=6y\)\(\Leftrightarrow y\left(x-6\right)=16\)
Xét Ư(16)
Bài 2:
Ta có :\(1-\dfrac{1}{2+\dfrac{1}{3}}=\dfrac{4}{7}\)
\(\dfrac{4}{7}=\dfrac{1}{\dfrac{7}{4}}=\dfrac{1}{1+\dfrac{3}{4}}=\dfrac{1}{1+\dfrac{1}{\dfrac{4}{3}}}=\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{3}}}\)
Vậy x=1 ; y=1 ;z=3