1. Để pt có 2 nghiệm cùng dương thì
\(\left\{{}\begin{matrix}\Delta'\ge0\\x_1.x_2\\x_1+x_2>0\end{matrix}\right.>0\)
<=>\(\left\{{}\begin{matrix}\left(m+3\right)^2-1.\left(4m-1\right)\ge0\\x_1.x_2=4m-1>0\\x_1+x_2=-[2\left(m+3\right)]>0\end{matrix}\right.\)
<=>
\(\left\{{}\begin{matrix}m^2+6m+9-4m+1=m^2+2m+10>0\\m>\dfrac{1}{4}\\m< -3\end{matrix}\right.\)
<=>-3<m<\(\dfrac{1}{4}\)