Ta có: \(\frac{-1}{4}\cdot\frac{15}{49}-\left(\frac{80}{100}+\frac{2}{3}\right):2\frac{1}{5}\)
\(=\frac{-15}{196}-\left(\frac{240}{300}+\frac{200}{300}\right)\cdot\frac{5}{11}\)
\(=\frac{-15}{196}-\frac{440}{300}\cdot\frac{5}{11}\)
\(=\frac{-15}{196}-\frac{2}{3}\)
\(=\frac{-45}{588}-\frac{392}{588}=\frac{-437}{588}\)