\(1,4\cdot\dfrac{15}{49}-\left(\dfrac{4}{5}+\dfrac{2}{3}\right):2\dfrac{1}{5}\\ =\dfrac{7}{5}\cdot\dfrac{15}{49}-\dfrac{22}{15}:\dfrac{11}{5}\\ =\dfrac{3}{7}-\dfrac{22}{15}\cdot\dfrac{5}{11}=\dfrac{3}{7}-\dfrac{2}{3}=-\dfrac{5}{21}\)
1,4.15/49-(4/5+2/3): 2/1/5
= 7/5. 15/49 - 2/15: 11/5
= 3/7 - 2/33
= 85/231