Ta có: \(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)
\(\Leftrightarrow x\cdot\frac{5}{8}=\frac{3}{4}\)
hay \(x=\frac{3}{4}:\frac{5}{8}=\frac{3}{4}\cdot\frac{8}{5}=\frac{24}{20}=\frac{6}{5}\)
Vậy: \(x=\frac{6}{5}\)
\(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)
\(\Leftrightarrow\frac{x}{2}+\frac{x}{8}=\frac{3}{4}\)
\(\Leftrightarrow4x+x=6\)
\(\Leftrightarrow5x=6\)
\(\Leftrightarrow x=\frac{6}{5}\)
=> x.(1/2 + 1/8)=3/4
= >x. 5/8 = 3/4
= > x = 3/4 : 5/8
=> x = 3/4 . 8/5
=> x = 24/20 = 6/5