(1 + 21) . ( 1 + 31) ... ( 1 + 99) à?
(1/2+1).(1/3+1).....(1/99+1)
=3/2.4/3.....100/99
=100/2=50
các bạn giúp mik với
P=(1-1/2^2)(1-1/3^2)..... (1-1/100^2)
mik cảm ơn trước nha!
(1/2 + 1).(1/3+ 1)...(1/99+ 1)
Chứng minh \(\dfrac{1}{5}\)< \(\dfrac{1}{4^2}\)+\(\dfrac{1}{5^2}\)+\(\dfrac{1}{6^2}\)+\(\dfrac{1}{7^2}\)+......+\(\dfrac{1}{99^2}\)+\(\dfrac{1}{100^2}\)<\(\dfrac{1}{3}\)
chứng tỏ rằng
\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{100^2}>\dfrac{99}{202}\)
Bài 1: Tìm x, biết
a, \(\left(4\frac{46}{65}+x\right).1\frac{1}{12}=5,75\) b, \(\frac{5}{4}-\left[\frac{3}{2}.x+0,5\right]=1\frac{1}{4}\)
CÁC BẠN GIÚP MIK NHANH NHANH CÁI NHA. MAI MIK PHẢI NỘP RỒI. CẢM ƠN CÁC BẠN TRƯỚC NHA ^^
Tính tổng sau: a) 1/2+1/6+1/12+1/20+1/30 b) 1/15+1/35+1/63+1/99+1/143 c) 1/6+1/12+1/20+1/30+1/42+1/56 d) 1/2+1/2^2+1/2^3+1/2^4+1/2^5 e) 1/7+1/7^2+1/7^3+...+1/7^100 f) 1+1/2*(1+2)+1/3*(1+2+3)+1/4*(1+2+3+4)+...+1/200*(1+2+3+..+200) g) (1/2+1)*(1/3+1)*(1/4+1)*..*(1/100+1) h) (1-1/2)*(1-1/3)*(1-1/4)*...*(1-1/2022) Giúp mk vs ạkkk
(1+1/1*3)*(1+1/2*4)*(1/3*5)*...*(1/99*101)
giúp tớ nữa nhé Nguyễn Lê Phước Thịnh kaka :)))
Cho \(B=\dfrac{1}{1^2}+\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{99^2}\). Chứng minh \(B< 1\dfrac{3}{4}\)
tính D =\(\dfrac{100-\left(1+\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{100}\right)}{\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}+....+\dfrac{99}{100}}\)
