Question

1. tìm x

a. x+\(\dfrac{3}{4}\)=\(\dfrac{1}{2}\)

b. \(\dfrac{5}{3}\). x=\(\dfrac{4}{7}\)

c. \(\dfrac{2}{3}\): x=\(\dfrac{-1}{4}\)

d. \(\dfrac{5}{9}\)- x=\(\dfrac{4}{3}\)

e.x +\(\dfrac{4}{17}\)=\(\dfrac{2}{34}\)

f. \(3\dfrac{4}{7}\): x=11

Answer 1

a)\(x+\dfrac{3}{4}=\dfrac{1}{2}\\ x=\dfrac{1}{2}-\dfrac{3}{4}=\dfrac{2}{4}-\dfrac{3}{4}=-\dfrac{1}{4}\)

b)\(\dfrac{5}{3}.x=\dfrac{4}{7}\\ x=\dfrac{4}{7}:\dfrac{5}{3}=\dfrac{4}{7}.\dfrac{3}{5}=\dfrac{12}{35}\)

c)\(\dfrac{2}{3}:x=\dfrac{-1}{4}\\ x=\dfrac{2}{3}:\dfrac{-1}{4}=\dfrac{2}{3}.\left(-4\right)=-\dfrac{8}{3}\)

d)\(\dfrac{5}{9}-x=\dfrac{4}{3}\\ x=\dfrac{5}{9}-\dfrac{4}{3}=\dfrac{5}{9}-\dfrac{12}{9}=\dfrac{-7}{9}\)

e)\(x+\dfrac{4}{17}=\dfrac{2}{34}\\ x=\dfrac{1}{17}-\dfrac{4}{17}=\dfrac{-3}{17}\)

f)\(3\dfrac{4}{7}:x=11\\ x=\dfrac{25}{7}:11=\dfrac{25}{7}.\dfrac{1}{11}=\dfrac{25}{77}\)