2, Ta có: \(4n-3⋮3n-2\)
\(\Rightarrow3\left(4n-3\right)⋮3n-2\)
\(\Rightarrow12n-9⋮3n-2\)
\(\Rightarrow12n-8-1⋮3n-2\)
\(\Rightarrow4\left(3n-2\right)-1⋮3n-2\)
\(\Rightarrow1⋮3n-2\)
\(\Rightarrow3n-2\in\left\{1;-1\right\}\)
\(\Rightarrow n\in\left\{1;\dfrac{1}{3}\right\}\)
Mà \(n\in Z\)
\(\Rightarrow n=1\)
Vậy n = 1
Ta có: 3^1000=(3^10)^100 = 59049^100
2^1500=(2^15)^100 = 32768^100
Vì 59049>32768 =>5904^9100>32768^100
=>3^1000>2^1500
1.
Ta có: 31000=(32)500=9500
21500=(23)500=8500
Vì 9500>8500=>31000>21500
2.
4n-3 3n-2
=>3(4n-3) 3n-2
=>12n-9 3n-2
=>12n-8-1 3n-2
=>4(3n-2) -1 3n-2
Đee4n-3 3n-2=>3n-2ϵ Ư(-1)
Ta có bẳng sau:
| 3n-2 | 1 | -1 |
| n | 1 | 1/2 |
| Kết luận | TM | L |
