Mình lo nha:
1.\(a^3+b^3=\left(a+b\right)^3-3ab\left(a+b\right)=1^3-3\left(-2\right).1=7\)
2.\(\left(2a+b\right)^2-\left(2b+a\right)^2=\left(2a+b+2b+a\right)\left(2a+b-2b-a\right)\)
\(=3\left(a+b\right)\left(a-b\right)=3\left(a^2-b^2\right)=3.\left(-4\right)=-12\)