\(VT=\dfrac{\left(x-y\right)^2+2xy}{x-y}\\ =x-y+\dfrac{2.1}{x-y}\\ \overset{Cauchy}{\ge}2\sqrt{\left(x-y\right)\dfrac{2}{x-y}}=2\sqrt{2}\)
Dấu "=" xảy ra <=> x=y=1.
Mấy bạn giúp mình bài này nha!
1) Tính A=(\(\sqrt{6}+\sqrt{2}\))*(\(\sqrt{3}-2\))*\(\sqrt{2+\sqrt{3}}\)
2) Cho x=4+\(\sqrt{10}\)
Tính A=\(\sqrt{3x+\sqrt{6x-1}}+\sqrt{3x-\sqrt{6x-1}}\)
3) Cho \(\sqrt{x}+\sqrt{y}-\sqrt{z}=0\)
CMR: \(\dfrac{1}{x+y-z}+\dfrac{1}{y+z-x}+\dfrac{1}{z+x-y}=0\)
4) Cho (\(\sqrt{x^2+5}+x\))*(\(\sqrt{y^2+5}+y\))=4
CMR: x+y=0
Cho 3 số x y z thỏa mãn x+y+z=xyz.Cm:\(\dfrac{\sqrt{\left(1+y^2\right)\left(1+z^2\right)}-\sqrt{1+y^2}-\sqrt{1+z^2}}{yz}+\dfrac{\sqrt{\left(1+z^2\right)\left(1+x^2\right)}-\sqrt{1+z^2}-\sqrt{1+x^2}}{zx}+\dfrac{\sqrt{\left(1+x^2\right)\left(1+y^2\right)}-\sqrt{1+x^2}-\sqrt{1+z^2}}{yz}=0\)
Cho các số thực dương x, y, z thỏa mãn : xyz=1.CMR:
\(\dfrac{1}{\left(\sqrt{xy}+\sqrt{x}+1\right)^2}+\dfrac{1}{\left(\sqrt{yz}+\sqrt{y}+1\right)^2}+\dfrac{1}{\left(\sqrt{xz}+\sqrt{z}+1\right)^2}\ge\dfrac{1}{3}\)
Giúp mk với , mk sắp thi r...
F = \(\dfrac{\sqrt{x}-\sqrt{y}}{xy\sqrt{xy}}:\left[\left(\dfrac{1}{x}+\dfrac{1}{y}\right).\dfrac{1}{x+y+2\sqrt{xy}}+\dfrac{2}{\left(\sqrt{x}+\sqrt{y}\right)^3}.\left(\dfrac{1}{\sqrt{x}}+\dfrac{1}{\sqrt{y}}\right)\right]\)
Rút gọn các biểu thức sau:
a, \(\dfrac{x\sqrt{x}+y\sqrt{y}}{\sqrt{x}+\sqrt{y}}-\left(\sqrt{x}-\sqrt{y}\right)^2\)
b, \(\sqrt{\dfrac{x-2\sqrt{x}+1}{x+2\sqrt{x}+1}}\) với \(x\ge1\)
1. Tính:
\(\sqrt{\dfrac{x-1+\sqrt{2x-3}}{x+2-\sqrt{2x+3}}}\)
2. Chứng minh:
a) \(\dfrac{\left(3\sqrt{xy}-6y.2x\sqrt{y}+4y\sqrt{x}\right)\left(3\sqrt{y}+2\sqrt{xy}\right)}{y\left(\sqrt{x}-2\sqrt{y}\right)\left(y-4x\right)}=1\)
b) \(\left(\sqrt{x}-\sqrt{y}-\dfrac{\sqrt{xy}}{\sqrt{x}+\sqrt{y}}\right)\left(\dfrac{\sqrt{x}}{\sqrt{x}+\sqrt{y}}+\dfrac{y}{\sqrt{x}-\sqrt{y}}-\dfrac{2\sqrt{xy}}{xy}\right)=\sqrt{x}+\sqrt{y}\)
a) \(\sqrt{\dfrac{x^2-2x+1}{x+2\sqrt{x}+1}}\)
b)\(\dfrac{x-1}{\sqrt{y}-1}.\sqrt{\dfrac{\left(y-2\sqrt{y}+1\right)^2}{\left(x-1\right)^4}}\)
Cho 0<x<1; 0<y<1. CMR:
\(x+y+x\sqrt{1-y^2}+y\sqrt{1-x^2}\le\frac{3\sqrt{3}}{2}\)
Cho 3 số dương x,y,z thỏa mãn x + y + z = xyz. Cmr:
\(A=\frac{\sqrt{\left(1+y^2\right)\left(1+z^2\right)}-\sqrt{1+y^2}-\sqrt{1+z^2}}{yz}+\frac{\sqrt{\left(1+z^2\right)\left(1+x^2\right)}-\sqrt{1+x^2}-\sqrt{1+z^2}}{xz}+\frac{\sqrt{\left(1+x^2\right)\left(1+y^2\right)}-\sqrt{1+x^2}-\sqrt{1+y^2}}{xy}=0\)
