Câu 1:
\(\overrightarrow{c}=x\cdot\overrightarrow{a}+y\cdot\overrightarrow{b}\)
\(\Leftrightarrow\left\{{}\begin{matrix}-1=x\cdot2+y\cdot\left(-2\right)\\-4=x\cdot1+y\cdot6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x-2y=-1\\x+6y=-4\end{matrix}\right.\)
=>x=-1; y=-1/2