1)
a)
$n_{MgSO_4} = \dfrac{12}{120} = 0,1(mol)$
$MgSO_4 \to Mg^{2+} + SO_4^{2-}$
$[Mg^{2+}] = [SO_4^{2-}] = \dfrac{0,1}{0,5} = 0,2M$
b)
$Mg^{2+} + 2OH^- \to Mg(OH)_2$
$n_{NaOH} = n_{OH^-} = 2n_{Mg^{2+}} = 0,2(mol)$
$V_{dd\ NaOH} = \dfrac{0,2}{1} = 0,2(lít)$