a: ĐKXĐ: x>=2
\(\dfrac{5}{3}\sqrt{9x-18}-2\sqrt{4x-8}=1\)
=>\(\dfrac{5}{3}\cdot3\sqrt{x-2}-2\cdot2\sqrt{x-2}=1\)
=>\(5\sqrt{x-2}-4\sqrt{x-2}=1\)
=>\(\sqrt{x-2}=1\)
=>x-2=1
=>x=3(nhận)
b: ĐKXĐ: \(x\in R\)
\(\sqrt{x^2-6x+9}-4=0\)
=>\(\sqrt{\left(x-3\right)^2}=4\)
=>\(\left|x-3\right|=4\)
=>\(\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)