\(n_{ZnO}=\dfrac{32.4}{81}=0.4\left(mol\right)\)
\(2Zn+O_2\underrightarrow{^{t^0}}2ZnO\)
\(0.4......0.2.......0.4\)
\(m_{Zn}=0.4\cdot36.5=14.6\left(g\right)\)
\(V_{kk}=5V_{O_2}=5\cdot0.2\cdot22.4=22.4\left(l\right)\)
\(n_{H_2SO_4}=\dfrac{392\cdot15}{98\cdot100}=0.6\left(mol\right)\)
\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
\(0.4.......0.4...........0.4........0.4\)
\(\Rightarrow H_2SO_4dư\)
\(m_{\text{dung dịch sau phản ứng}}=14.6+392-0.4\cdot2=405.8\left(g\right)\)
\(m_{ZnSO_4}=0.4\cdot161=64.4\left(g\right)\)
\(m_{H_2SO_4\left(dư\right)}=\left(0.6-0.4\right)\cdot98=19.6\left(g\right)\)
\(C\%ZnSO_4=\dfrac{64.4}{405.8}\cdot100\%=15.8\%\)
\(C\%H_2SO_4\left(dư\right)=\dfrac{19.6}{405.8}\cdot100\%=4.82\%\)
