PT: \(C+O_2\underrightarrow{t^o}CO_2\)
Ta có: \(n_{O_2}=\dfrac{0,56}{22,4}=0,025\left(mol\right)\)
a, Theo PT: \(n_C=n_{O_2}=0,025\left(mol\right)\)
\(\Rightarrow m_C=0,025.12=0,3\left(g\right)\)
b, Theo PT: \(n_{CO_2}=n_{O_2}=0,025\left(mol\right)\)
\(\Rightarrow V_{CO_2}=0,025.22,4=0,56\left(l\right)\)