a. \(v_{AB}=\dfrac{s}{t}=\dfrac{6}{\dfrac{18}{60}}=20\left(\dfrac{km}{h}\right)\)
b. \(v_{AC}=\dfrac{s_{AC}}{t_{AC}}=\dfrac{6+8,1}{\dfrac{18}{60}+\dfrac{8,1}{9\cdot3,6}}=\dfrac{282}{11}\left(\dfrac{km}{h}\right)\)
c. Tới C lúc: \(7h20p+18p+\dfrac{8,1}{9\cdot3,6}=7h53p\)