Question

Answer 1

\(\dfrac{1}{3}x-0,75x+\dfrac{1}{6}x-\dfrac{27}{32}=0\\ x\left(\dfrac{1}{3}-\dfrac{3}{4}+\dfrac{1}{6}\right)=\dfrac{27}{32}\\ \left(\dfrac{4-9+2}{12}\right)x=\dfrac{27}{32}\\ -\dfrac{1}{4}x=\dfrac{27}{32}\\ x=\dfrac{-27}{8}\)

Answer 2

=>1/3x-1/4x+1/6x-27/32=0

=>1/4x=27/32

=>x=27/8

Answer 3

=>1/3x-1/4x+1/6x-27/32=0

=>1/4x=27/32

=>x=27/8